Calorimetry Calculator
Heat joules from mass, specific heat, and temperature rise.
What it does
Calorimetry prices temperature changes: mass times specific heat times degrees gives joules absorbed or released. Heating water dominates lab and kitchen math because its specific heat runs high.
The tool above takes grams, specific heat, and the rise in Celsius degrees. It returns joules with kilojoules and food calories beside them.
The default of 500 g water up 80 C takes 167,360 J (167.36 kJ, 40 kcal). A 100 g sample up 10 C takes 4,184 J, exactly 1 kcal by the calorie definition.
The q = mcT form follows Khan Academy chemistry units with NIST water heat references behind the 4.184 constant. Both exclude phase changes, which run on latent heats instead.
How to use
- Enter the mass in grams.
- Enter the specific heat (4.184 for water).
- Enter the temperature rise in Celsius degrees.
- Read joules first for the SI answer.
- Use kcal for food and diet contexts.
Formula
- mass
- Grams heated or cooled.
- c
- Joules per gram per degree.
- delta T
- Rise in Celsius degrees (equals kelvin).
Celsius degrees equal kelvin steps, so either scale works for differences. Sign flips for cooling; magnitude stays the same.
Worked example
Example: 500 g water up 80 C
Defaults: 500 g, 4.184, rise 80.
- Multiply: 500 x 4.184 = 2092 per degree.
- Heat: 2092 x 80 = 167,360 J.
- Kilo: 167,360 / 1000 = 167.36 kJ.
- Food: 167,360 / 4184 = 40 kcal.
- Tool shows 167,360 J, 167.36 kJ, 40 kcal.
Reference table
| Substance | c (J/gC) | 500 g up 80 C |
|---|---|---|
| Water | 4.184 | 167,360 J |
| Aluminum | 0.897 | 35,880 J |
| Iron | 0.449 | 17,960 J |
| Copper | 0.385 | 15,400 J |
Limits
- No phase change; boiling needs latent heat.
- Constant specific heat assumed across the span.
- Heat loss to vessels ignored.
- Sign convention: absorbed positive here.
Common mistakes
- Using milliliters as grams for non water liquids.
- Entering Fahrenheit degrees instead of Celsius.
- Forgetting phase change at boiling point.
- Mixing kJ with J mid calculation.
- Reading kcal as physics calories (1000x off).
Try it yourself
Quick checks. Answers sit tucked under each question.
100 g water up 10 C?
100 x 4.184 x 10 = 4,184 J = 1 kcal.
200 g aluminum up 50 C?
200 x 0.897 x 50 = 8,970 J.
Joules in 1 kcal?
4184 J by definition.
Questions
What is the calorimetry formula?
q = mcT: grams times specific heat times degrees.
Why 4.184 for water?
It defines the calorie: heating 1 g water 1 C takes 4.184 J.
Celsius or kelvin?
Either for differences; degree steps match exactly.
What about boiling?
Sensible heat stops at the phase line; latent heat takes over.
Joules vs calories?
4184 J per food kcal. Physics calories are thousandths of that.
Cooling negative?
Same magnitude released; sign follows your convention.